User Contributed MET/CAL Procedure ============================================================================= INSTRUMENT: Bell Distribution Box Sub DATE: 07-Dec-95 AUTHOR: User Contributed REVISION: ADJUSTMENT THRESHOLD: 70% NUMBER OF TESTS: 11 NUMBER OF LINES: 78 CONFIGURATION: Datron 1281 ============================================================================= STEP FSC RANGE NOMINAL TOLERANCE MOD1 MOD2 3 4 CON 1.001 JMP 2.002 1.002 EVAL 2.001 DISP Set the 1550A to 0,0,0. 2.002 HEAD [27][91]5m[27][91]7m1281 Zero Being Performed[27][91]0m 2.003 IEEE [@1281]*RST[D1000] 2.004 IEEE [@1281]DCV 10[D1000] 2.004 IEEE [@1281]ZERO?[T0][I$] 2.005 HEAD ÍÍ Channel [MEM] Linearity Tests ÍÍ 2.006 DISP Set the 1550A to 0,9,0. 2.007 IEEE [@1281]RDG?[I] 2.008 MEM/ 9 2.009 MEME >1 2.010 IEEE [@1281]RDG?[D2000][I] 2.011 MATH mem = (mem/m[1])*1000 2.012 MATH MEM1=9000 2.013 MEME 2.014 MEMC æî 45.0U 3.001 DISP Set the 1550A to 0,8,0. 3.002 IEEE [@1281]RDG?[D2000][I] 3.003 MATH mem = (mem/m[1])*1000 3.004 MATH MEM1=8000 3.005 MEME 3.006 MEMC æî 45.0U 4.001 DISP Set the 1550A to 0,7,0. 4.002 IEEE [@1281]RDG?[D2000][I] 4.003 MATH mem = (mem/m[1])*1000 4.004 MATH MEM1=7000 4.005 MEME 4.006 MEMC æî 45.0U 5.001 DISP Set the 1550A to 0,6,0. 5.002 IEEE [@1281]RDG?[D2000][I] 5.003 MATH mem = (mem/m[1])*1000 5.004 MATH MEM1=6000 5.005 MEME 5.006 MEMC æî 45.0U 6.001 DISP Set the 1550A to 0,5,0. 6.002 IEEE [@1281]RDG?[D2000][I] 6.003 MATH mem = (mem/m[1])*1000 6.004 MATH MEM1=5000 6.005 MEME 6.006 MEMC æî 45.0U 7.001 DISP Set the 1550A to 0,4,0. 7.002 IEEE [@1281]RDG?[D2000][I] 7.003 MATH mem = (mem/m[1])*1000 7.004 MATH MEM1=4000 7.005 MEME 7.006 MEMC æî 45.0U 8.001 DISP Set the 1550A to 0,3,0. 8.002 IEEE [@1281]RDG?[D2000][I] 8.003 MATH mem = (mem/m[1])*1000 8.004 MATH MEM1=3000 8.005 MEME 8.006 MEMC æî 45.0U 9.001 DISP Set the 1550A to 0,2,0. 9.002 IEEE [@1281]RDG?[D2000][I] 9.003 MATH mem = (mem/m[1])*1000 9.004 MATH MEM1=2000 9.005 MEME 9.006 MEMC æî 45.0U 10.001 DISP Set the 1550A to 0,1,0. 10.002 IEEE [@1281]RDG?[D2000][I] 10.003 MATH mem = (mem/m[1])*1000 10.004 MATH MEM1=1000 10.005 MEME 10.006 MEMC æî 45.0U 11.001 END